Math, asked by jodhgill3783, 12 hours ago

Q15. Vansh travels 3 km in the East
and turns to South and moves 4 km.
How far is he from the starting point?
(ਵੰਸ਼ 3 ਕਿ.ਮੀ. ਪੂਰਬ ਵੱਲ ਜਾਂਦਾ ਹੈ ਅਤੇ ਫਿਰ ਦੱਖਣ
ਵੱਲ ਮੁੜਦਾ ਹੈ 'ਤੇ 4 ਕਿ.ਮੀ. ਤੁਰਦਾ ਹੈ। ਉਹ ਮੂਲ ਬਿੰਦੂ
ਤੋਂ ਕਿੰਨਾ ਦੂਰ ਹੈ?) *
05 km(5 ਕਿ.ਮੀ.)
O 6 km(6 ਕਿ.ਮੀ.)
O 2 km(2 ਕਿ.ਮੀ.)
0 10 km(10 ਕਿ.ਮੀ.)
Mv .​

Answers

Answered by Sauron
115

Answer:

Option 1) 5 km

The distance from the starting point to Vansh's final position is 5 km.

Step-by-step explanation:

Vansh travelled = 3 km towards east

Then he travels = 4 km towards south

Distance from starting point.

Starting point is A and final point is C. So, the distance from the starting point to the final point is x.

We can solve it by Pythagoras theorem,

  • Hypotenuse = x = AC
  • Base = 3km = AB
  • Height = 4km = BC

(Hypothenuse)² = (Base)² + (Height)²

⇒ (x)² = (3)² + (4)²

⇒ x² = 9 + 16

⇒ x² = 25

⇒ x = √25

x = 5

Hypothenuse = 5 km

Therefore, the distance from the starting point to Vansh's final position is 5 km.

Attachments:
Answered by Itzheartcracer
60

Given :-

Vansh  travels 3 km in the East  and turns to South and moves 4 km.

To Find :-

Far from starting point

Solution :-

We know that

Hypotenuse² = Base² + Height²

H² = 3² + 4²

H² = 9 + 16

H² = 25

√H² = √25

H = 5

Hence,

Vansh is 5 km far from the starting point

Option A is correct.

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