Q15. Vansh travels 3 km in the East
and turns to South and moves 4 km.
How far is he from the starting point?
(ਵੰਸ਼ 3 ਕਿ.ਮੀ. ਪੂਰਬ ਵੱਲ ਜਾਂਦਾ ਹੈ ਅਤੇ ਫਿਰ ਦੱਖਣ
ਵੱਲ ਮੁੜਦਾ ਹੈ 'ਤੇ 4 ਕਿ.ਮੀ. ਤੁਰਦਾ ਹੈ। ਉਹ ਮੂਲ ਬਿੰਦੂ
ਤੋਂ ਕਿੰਨਾ ਦੂਰ ਹੈ?) *
05 km(5 ਕਿ.ਮੀ.)
O 6 km(6 ਕਿ.ਮੀ.)
O 2 km(2 ਕਿ.ਮੀ.)
0 10 km(10 ਕਿ.ਮੀ.)
Mv .
Answers
Answer:
Option 1) 5 km
The distance from the starting point to Vansh's final position is 5 km.
Step-by-step explanation:
Vansh travelled = 3 km towards east
Then he travels = 4 km towards south
Distance from starting point.
Starting point is A and final point is C. So, the distance from the starting point to the final point is x.
We can solve it by Pythagoras theorem,
- Hypotenuse = x = AC
- Base = 3km = AB
- Height = 4km = BC
★ (Hypothenuse)² = (Base)² + (Height)²
⇒ (x)² = (3)² + (4)²
⇒ x² = 9 + 16
⇒ x² = 25
⇒ x = √25
⇒ x = 5
Hypothenuse = 5 km
Therefore, the distance from the starting point to Vansh's final position is 5 km.
Given :-
Vansh travels 3 km in the East and turns to South and moves 4 km.
To Find :-
Far from starting point
Solution :-
We know that
Hypotenuse² = Base² + Height²
H² = 3² + 4²
H² = 9 + 16
H² = 25
√H² = √25
H = 5
Hence,
Vansh is 5 km far from the starting point
Option A is correct.