Question

Q16 & Q17
Pls help solve

Answer 1

Q16 (I) 400
(ii) 118
This is correct answer and I don't know 3 rd part

Answer 2

Q 16 ).

i ) No defective bulb :- E

Total bulb :- 700

No defective ( Zero defective ) :- 400

P ( No defective bulb ) =
no.of no defective bulb / total bulb

P ( E ) :- 400/700

P ( E ) :- 4/7

ii ) Defective bulb from 2 to 6 :- E

Outcomes :- 48 + 41 + 18 + 8 + 3 = 118

P ( E ) = 118 /700

P ( E ) = 59/350

iii ) Defective bulb less than 4 :- E

Outcomes :- 400 + 180 +48 + 41 = 669

P ( E ) = 669/700


Q 17

i ) No defective part :- E

Outcomes :- 50

Total outcomes :- 200


P ( E ) = 50/200


ii ) At least 1 defective part :- E

Out comes :- total from 1 defective to 13 defective = 150

P ( E ) = 150/200

iii ) Not more than 5 defective part :- E

Out comes :- 134

P ( E ) = 134 /200


iv ) more than 13 defective part :- E

outcomes :- 0

P ( E ) = 0/200

P ( E ) = 0