Question

Q17:Arrange the following in the decreasing order of their shrillness(i)sound with frequency of 2.5hz(ii)sound making 120 vibrations every minute(iii)sound with a time period of vibration of 2 seconds​

Answer 1

Answer:

i > ii > iii

Explanation:

Shrillness increases with increase in frequency of the sound.

Given frequencies:

i) 2.5 Hz

ii) 120/60s = 2Hz

iii) $\\\tt f = \dfrac{1}{Time\ Period} = \dfrac{1}{2} = 0.5Hz$

Therefore decreasing order of shrillness will be:

i > ii > iii

Answer 2

Required Answer :-

We know that

Frequency = Vibration/Time

1 min = 60 sec

Frequency = 120/60

Frequency = 2 hertz

Now

In 3rd case

Frequency = 1/Time

Frequency = 1/2

Frequency = 0.5 hertz

Now

We may see that

2.5 > 2 > 0.5

Hence

The correct order will be

i > ii > iii