Question

Q19. Factorise : 64a3 â 27b3 -144a2b + 108ab2.

Answer 1

Solution :

64a³ -27b³ - 144a²b + 108ab²

= (4a)³-(3b)³-3×(4a)²(3b)

+ 3×(4a)(3b)²

= ( 4a - 3b )³

= (4a-3b)(4a-3b)(4a-3b)

••••

Answer 2

Answer:

Here is your answer

Thank you