Question

Q2. A & B can finish a work in 30 days. They worked for 20 days and then B left. The remaining work was
done by A alone in 20 more days. In how many days can A alone finish the work?​

Answer 1

Step-by-step explanation:

A+B's 20 day's work=301×20=32

Remaining work=1−32=33−2=31

Now, 31rd work is done by A in 20 days.

∴ The whole work will be done by A in 20×3=60 days. 

Answer 2

Answer:

Answer is 60 days

Step-by-step explanation:

Because the work b is 1

And the work of a is 1/2

Then, inverce the 1/2 =2

2 x 30 = 60 days