Question

Write the first five terms of the arithmetic sequence whose first term is 8 and whose common difference is -6.

Answer 1

Answer:

8, 2, -4, -10, -16,...

Step-by-step explanation:

Let the first term be 'a' = 8

Let the common difference be 'd' = -6

1st term = a = 8

2nd term = a + d = 8 + (-6) = 8 - 6 = 2

3rd term = a + 2d = 8 + 2(-6) = 8 - 12 = -4

4th term = a + 3d = 8 + 3(-6) = 8 - 18 = -10

5th term = a + 4d = 8 + 4(-6) = 8 - 24 = -16

Therefore, the first 5 terms of the AP are 8, 2, -4, -10, -16,...

Answer 2

Step-by-step explanation:

ANSWER:-

Given :-

• The first term as 8
• The common difference as -6

To find:-

The first 5 terms of the AP

Let's Do!

For this, we need to use the formula:-

$\sf{a_n = a+ (n-1)d}$

• Where a_n is the nth term
• Where a is the first term
• Where n is the number of terms
• Where d is the common difference.

$\sf{a_n = a+ (n-1)d}$

$\sf{a_n = 8+ (5-1)(-6)}$

$\sf{a_n = 8 - 24}$

$\sf{a_n = -16 }$

So, If the 5th term is -16, the 4th term is -10, -4, 2, 8

And hence, the sequence is -16, -10, -4, 2, 8.