Question

Q2. A computer employs RAM chip of 256 x 8 and ROM chips of 512 x 8. The computer

system needs 2048 x 8 (2k) memory .[1k bytes of RAM and 1k bytes of ROM].

How would you:

(i) Draw a memory address map.

(ii) Show address range in hexadecimal for RAM and ROM.

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Answer 1

Explanation:

A computer employs RAM chips of 256 × 8 and ROM chips of 1024 × 8. The computer system needs 2K bytes of RAM, 4K bytes of ROM, and four interface units, each with four registers. A memory-mapped I/O configura­tion is used. The two highest-order bits of the address bus are assigned 00 for RAM, 01 for ROM, and 10 for interface registers.

a. How many RAM and ROM chips are needed?

b. Draw a memory-address map for the system.

c. Give the address range in hexadecimal for RAM, ROM, and interface

step by step explanation

Size of RAM chip

The memory of RAM required k bytes bytesbits

Total number of RAM chips required = Chips

Size of ROM chip =

The memory of ROM required = k bytesbytes=bits

Total number of ROM chips required=Chips

Hence, RAM chips and ROM chips are required

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