Q2. A solution contains 2.5 gm of sugar in 50 gm of water. Calculate the concentration in terms of mass by mass percentage of the solution
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Answer:
(i) Mass of sugar = 34.2 g
No. of moles of sugar =
Mol.mass
34.2
=
342
34.2
=0.1
Mass of water = (214.2-34.2)=180g=
1000
180
kg
No. of moles of water =
18
180
=10 mole
Molarity =
Mass of water in kg
No. of moles of sugar
=
180
0.1
×1000
=0.555M
Thus, the molarity of sugar is 0.555 M
(ii) Total number of moles =10.0+0.1=10.1
Mole fraction of sugar =
Total number of moles
No. of moles of sugar
=
10.1
0.1
=0.0099
Thus mole fraction of sugar syrup is 0.0099
Explanation:
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