Question

Q2. A tent of a crous is such that its lower part is cylindrical and the upper part is conical. The
diameter of the base of the tent is 48 m and the height of the cylindrico parts 15 m. Total
height of the tent is 33 m Find the area of canvas requred to make the tent. Also ind volume of
air in the ten​

Answer 1

$\boxed{\bold{Radius\: of\: the\: base\: = \frac{Diameter}{2}}}$

$\implies\bold{R = \frac{48}{2}}$

$\implies\bold{R=24m}$

Height of the cylindrical part = 15 m

Curved Surface Area of Cylinder = 2πrh

$\implies\bold{CSA=2\times3.14\times24\times15}$

$\boxed{\bold{\therefore\:CSA=2260.8\:m^2}}$

Curved Surface Area of Cone = πrl

Slant Height of Cone,  $\boxed{\bold{l= \sqrt{r^2 + h^2}}}$

$\implies\bold{l=\sqrt{24^2+18^2}}$

$\implies\bold{l=\sqrt{576+324}}$

$\implies\bold{l=\sqrt{900}}}$

$\boxed{\bold{\therefore Slant\: height\: of\: the\: cone\:=30\:cm}}$

Curved Surface Area of Cone = πrl

$\implies\bold{CSA=3.14\times24\times30}}$

$\boxed{\bold{\therefore\:CSA=2260.8\:m^2}}$

Total area of the cylindrical part and the conical part = 2640 + 4664 

$\boxed{\bold{\therefore The\: area\: of\: the\: canvas\: required\: = 4521.6\:m^2}}$