Q2. A thermally insulated pot has 150 g ice at temperature 0°C. How much steam of 100°C
has to be mixed to it, so that water of temperature 50°C will be obtained?
(Given : latent heat of melting of ice = 80 cal/g,
latent heat of vaporization of water = 540 cal/g,
specific heat of water = 1 cal/g°C)
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Explanation:
A thermally insulated pot has 150 g ice at temperature 0°C. How much steam of 100 C has to be mixed to it, so that water of temperature 50 C will be obtained? =50m. 590m=19500
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