Question

Q2. Find the zeroes of the given quadratic polynomials and verify the
relationship between the zeroes and the coefficients. 6x 2 - 3 - 7x.
O Solve
19 and​

Answer 1

Step-by-step explanation:

6x² -3 - 7x

6x² -7x -3=0

6x ² - ( 9-2)x -3=0

6x² -9x + 2x -3=0

3x( 2 x -3) +1( 2x-3) =0

( 2x -3) ( 3x +1) =0

x = 3/2 ; x = -1/3

on comparing ax² +bx +c=0

alpha = 3 /2 ,beta = -1/3

a= 6 , b= -7, c = -3

relationship b/w zeroes

i) sum of zero

alpha +beta = -b/a

3/2 + ( -1/3) = -( -7 / 6)

3 /2 - 1/3 = 7 /6

9-2/6 = 7/6

7/6 =7/6

ii) product of zero

alpha ×beta = c/a

3/2 × -1/3 = -3/6

-3 /6 = -3/6

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