Question

Q2. If x = 0 and x = −2 be the zeros of the polynomial p(x) = x³ − 2x² + 3ax + b. Find

the values of a and b.

Answer 1

Hi friend!!!!

Given, x = 0 and x = −2 be the zeros of the polynomial p(x) = x³ − 2x² + 3ax + b.

→p(0)=0

0-0+0+b=0

b=0------(1)

and also

→p(-2)=0

(-2)³-2(-2)²+3a(-2)+b=0

=-8-8-6a+b=0

since b=0

→-16-6a=0

a=16/(-6)

a=-8/3

I hope this will help u ;)

Answer 2

a=-8/3
b=0
hope this will help you