Q2. If x = 0 and x = −2 be the zeros of the polynomial p(x) = x³ − 2x² + 3ax + b. Find
the values of a and b.
Answers
Answered by
3
Hi friend!!!!
Given, x = 0 and x = −2 be the zeros of the polynomial p(x) = x³ − 2x² + 3ax + b.
→p(0)=0
0-0+0+b=0
b=0------(1)
and also
→p(-2)=0
(-2)³-2(-2)²+3a(-2)+b=0
=-8-8-6a+b=0
since b=0
→-16-6a=0
a=16/(-6)
a=-8/3
I hope this will help u ;)
Given, x = 0 and x = −2 be the zeros of the polynomial p(x) = x³ − 2x² + 3ax + b.
→p(0)=0
0-0+0+b=0
b=0------(1)
and also
→p(-2)=0
(-2)³-2(-2)²+3a(-2)+b=0
=-8-8-6a+b=0
since b=0
→-16-6a=0
a=16/(-6)
a=-8/3
I hope this will help u ;)
CherrySharma2003:
Ty..!!
welcome ;)
Answered by
1
a=-8/3
b=0
hope this will help you
b=0
hope this will help you
welcome:)
oh sorry
sorry for what?
this was answered by someother user
no i have calculate it
oh..!! know I got it..!!
Even I got confused at 1st..!!
Ty..!! Both of you..!! *DhanyaDA and udaykaushik1..!!
TRY what
it's not TRY..it's TY..and with TY I mean thank you..T=Thank Y=You..
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