Question

Q2. solve the equations
I. 3(x=2) 2 (x-1) = 7
2. x-3/5-2= 2x/5
Answer the question fast​

Answer 1

1. 3(x=2) 2 (x-1) = 7

3(x=2) - 2 (x-1) = 7

3x + 6 - 2x + 2 = 7

x + 8 = 7

x = 7 - 8

x = -1

2. x-3/5-2= 2x/5

x - 3/5 - 10/5 = 2x/5

x - 13/5 ÷ 2x/5

- 13 × 5/5 = 2x - x

- 65/5 = x

x = - 13

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Answer 2

Given,

• 3(x+2)−2(x−1)=7

⇒3x+6−2x+2=7

⇒x+8=7

Subtract 8 on both sides,

x+8−8=7−8

⇒x=−1

Given,

• 2x−5=3(x−5)

⇒2x−5=3x−15.

Transpose x terms on one side, we get

⇒3x−2x=−5+15

⇒x=10.

Therefore, value of x is 10.