Question

Q2. The zeroes of x2 – 2x – 8 are

(a) (2,-4) (b) (4, -2)

(c) (-2, -2) (d) (-4, -4)​

Answer 1

Answer:

(B)

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x-4)(x+2)=0

x=(4,-2)

Step-by-step explanation:

Answer 2

Answer:(4,-2)

Step-by-step explanation:

p(x)=x^2-2x-8

Factorise it by mid term factorisation

So, x^2-2x-8

=x^2-4x+2x-8

=x(x-4)+2(x-4)

=(x+2)(x-4)

=(x+2)(x-4)=0

=>x=(4,-2)