Question

Q2.
Triangle ABC is isosceles with AB - AC -6 cm, BC = 8 cm.
The height AD from A to BC is 7 cm.
Find the area of triangle ABC.
What will be the height from Con AB?

Answer 1

Answer:

28

$area \: of \: triangle = \frac{1}{2} \times b \times h$

=1/2

$= \frac{1}{2} \times 8 \times 7 \: cm ^{2} \\ =28 \: cm {}^{2}$