Question

Q20. A piece of wire is 160 cm long. If it is bent to form a square and a rectangle
turn by turn then find:
(i) the side of the square
(ii) breadth of rectangle
with length 20 cm

help me pls​

Answer 1

$\sf \Large Solution!!$

$\sf \large Given:$

$\sf \to Length\:of\:wire=160\:cm$

$\sf \large To\:find:$

$\sf \to Side\:of\:the\:square.$

$\sf \to Breadth\:of\:rectangle\:with\:length\:20\:cm$

$\sf \boxed{Length\:of\:wire\:is\:the\:perimeter\:of\:both\:the\:shapes.}$

$\sf \large So,\:we\:know\:that\:square\:has\:4\:equal\:sides.$

$\sf \to 4\times Side=160\:cm$

$\sf \to Side=\frac{160}{4}=40\:cm$

$\sf \large Length\:of\:rectangle\:is\:given\:as\:20\:cm.\:So,$

$\sf \to Perimeter=2(Length+Breadth)$

$\sf \to 160=2(20+Breadth)$

$\sf \to \frac{160}{2}=20+Breadth$

$\sf \to 80=20+Breadth$

$\sf \to Breadth=80-20=60\:cm$

Thanks for asking!! :)