Question

Q22. If a^2+b^2+c^2=14 and a+b+c= 6, find ab + bc + ca.
or
if x+1/x- 5 find the value of x^4 +1/x^4​

Answer 1

Answer:

(a+b+c)^2=a^2+b^2+c^2 +2(ab+bc+can)

then

36=14+2(ab+bc+ca)

ab+bc+ca= 11

ok

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