Question

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Q23. Find the middle term in the expansion of $\bigg\lgroup\sf{x^2-\dfrac{2}{x}}\bigg\rgroup$​

Answer 1

‏‏‎ ‎Meristematic Cells have a prominent nucleus and dense Cytoplasm but lack

Vacuole.

Answer 2

Answer:

Given that to find middle term in expansion of (20x−x2b)12

n=12⇒ even

for even number middle term =(2n+1)th

middle term =(212+1)th⇒7

We know that Tr+1= nCr(a)n−rbr

T7=T6+1= 12C6(29x)12−6(x2−b)6

=6!6!12!26a6x6x12b6

=6×5×4×3×2×1×6!

12×11×10×9×8×7×6!26