Question

Q24. In the Daniel cell Zn/Zn2+
(0.01M) // Cu2+ (1.OM)/Cu , The emf
of the cell is E1 volt .when the conc.
of Zn2+ is 1.0 M and Cu2+ 0.01M, the
emf changed to E2. What is the
relation between E1 and E2 *
O a) E1 > E2
O b) E1 < E2
O c) E1 = E2
O d) E1 = E2 = 0​

Answer 1

Answer:

$\huge\underline\bold\red{AnsWeR}$

a) E1 >E2

Answer 2

Answer:

Option (a) is ur answer.....