Question

Q26 A mass of 4 kg rests on a horizontal plane. The plane is gradually inclined until at an angle = 30° with the horizontal, the mass just begins to slide. What is the coefficient of static friction between the block and the surface? 3​

Answer 1

Answer:

We know that,

Mass m=4kg

angle θ=15

0

Now, the normal force is

N=mg

N=4×10

N=40N

Now, frictional force always opposes direction of motion

So,

F

f

=mgcosθ

μN=4×10×cos15

0

μ×40=40×0.96

μ=0.96

Hence, the friction is 0.96

f