Question

Q26. What is the angle between the planes 3x-
2y+11=0 and 32-7=0​

Answer 1

Step-by-step explanation:

We have,

π

1

:2x+2y−3z=5

π

2

:3x−3y+5z=3

cos0=

9+4+4

9+9+25

∣6−6−15∣

cos0=

17

43

15

θ=cos

−1

(

17

43

15

)

Then,

We get θ=cos

−1

(

17

43

15

)

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