Question

Q3.a) A block of wood is floating in water at 0°C. The temperature
of water is slowly raised from 0°C to 10°C. How will the volume of
block above water level change with the rise in temperature from
0°C to 10°C. Justify your answer with proper explanation. ​

Answer 1

Answer:

A block of wood is floating on water at 0ºC with volume V0 above water. When the temperature of water increases from 0 to 10 ºC, the change in the volume of the block that is above water

Answer 2

Answer:

First increases then decreases.

Explanation:

Step 1: Water behaves strangely when heated from 0 °C to 4.0 °C. Its density surprisingly rises from 0 0 C to 4 0 C before falling. The percentage of the block above the water will undoubtedly rise since the density of the block will reduce upon heating up to 4 0 C. Following that, the portion of the block above the water will reduce as the decrease in water density overpowers the negligible decrease in wood density.

At 4oC, water has its highest density. Therefore, as it is heated from 0°C to 10°C, its density first rises, then it decreases, causing a decrease in volume at first, then an increase in volume later.

Step 2: At 0°C, a block of iron floats in mercury with a fraction of its volume buried; at 60°C, a fraction of its volume is seen to be submerged. The ratio k1/k2 can be written as if the coefficient of volume expansion for iron is Fe and that for mercury is Hg.

Water loses volume as its density rises when heated above 0°C; this impact is visible up to 4°C. Since ice has a maximal density at 4 degrees Celsius, as the temperature drops, the volume grows.

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