Q3.A powder is available in two packs , a tin can with a square base of side 5
cm and having height 12 cm and one with a circular base of radius 3.5 cm and
having height 10 cm. Which of these has greater capacity and by how much?
Answers
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1
Given : A circle with centre O and a chord AB
Let M be the mid point of AB and OM is joined and produced to meet the minor arc AB at N
To prove : M is the mid point of arc AB
Construction : Join OA, OB
Proof: ∵ M is mid point of AB
∴ OM ⊥ AB
In AOAM and OBM,
OA = OB (Radii of the circle)
OM = OM (common)
AM = BM (M is mid point of AB)
∴ ∆OAM = ∆OBM (SSS criterian)
∴ ∠AOM = ∠BOM (c.p.c.t.)
⇒ ∠AOM = ∠BOM
But these are centre angles at the centre made by arcs AN and BN
∴ Arc AN = Arc BN
Hence N divides the arc in two equal parts
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Answer:
We can calculate the volume using the formula: Substitute l=9, b=9 and h=12 in above formula. Hence, the capacity of square base tin is 972 cm³.
Step-by-step explanation:
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