Q3. A semi-circular sheet of
diameter 14cm is bent to form a conical cup. Find the height of the conical cup
Answers
Answer:
311.08 cm cube
Step-by-step explanation:
r=14/2=7cm
area of semi circle = CSA of cone
1/2πr^2=πrl
πr(1/2r)=πr(l)
1/2r=l
1/2×7=l
l=3.5
by pythagores theorem
h^2=p^2+b^2
p^2=h-^2-b^2
h^2=(3.5)^2-(7)^2
h=√-12.25+49
h=√36.75
h=6.06cm
volume =1/3πr^2h
1/3×22/7×7×7×6.06
=311.08cm³
Answer:
Step-by-step explanation:
Answer Expert Verified
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pinquancaro
The capacity of the cup is 77.77 cm³.
Step-by-step explanation:
Given : A semicircle sheet of paper of diameter 14 cm is bent to form an open conical cup.
To find : The capacity of the cup ?
Solution :
A semicircle sheet of paper of diameter 14 cm.
The radius is R=7 cm.
Let radius and height of the conical cup be 'r' and 'h' respectively.
Circumference of the base of the cone = Length of arc of the semi-circle
i.e.
Slant height of the conical cup = Radius of the semi-circular sheet
We know that,
Height of the conical cup = 6.06 cm
The capacity of the conical cup is given by,
Therefore, the capacity of the cup is 77.77 cm³.
#Learn more
A semicircular sheet of paper of diameter 28 cm is bent into an open conical cup. find the depth and the capacity of the cup
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r=14/2=7cm
area of semi circle = CSA of cone
1/2πr^2=πrl
πr(1/2r)=πr(l)
1/2r=l
1/2×7=l
l=3.5
by pythagores theorem
h^2=p^2+b^2
p^2=h-^2-b^2
h^2=(3.5)^2-(7)^2
h=√-12.25+49
h=√36.75
h=6.06cm
volume =1/3πr^2h
1/3×22/7×7×7×6.06
=311.08cm³