Question

Q3 Find the smallest ho. Which do when divided
by 15, 60,30 leaves remainder
7 in each
case?​

Answer 1

$\Huge\mathrm{\green{Answer:-127}}$

we take the lcm of 30, 40 ,60

= 2x2x2x3x5=120 in 120

=we add 7 by 30 , 40 and 60 leaves the remainder 7 in each case

= in 120 we add 7,

=so answer is 127.

Answer 2

Firstly we have to take L.C.M of mentioned number.

That Is,

15,60,30=240

NOW SUBTRACT 240 FROM 7 THE ANSWER YOU'LL GET WILL BE 233

HENCE 233 IS THE SMALLEST NUM WHICH WHEN SUBTRACTED FROM 15, 60,30 leaves remainder

7 in each

case?