Question

Q3. If the numbers x+3,2x+1 and X-7 are in A.P., find the value of X.

Answer 1

if x+3,2x+1,x-7 are in A.P
a2-a1=a3-a2
2x+1-x-3=x-7-2x-1
x-2=-x-8
x+x=-8+2
2x=-6
x=-6/2
x= -3

Answer 2

Answer:

The value of x is -3.

Step-by-step explanation:

Given that the numbers x+3, 2x+1 and x-7 are in AP.

It means that the difference between two consecutive terms should be equal.

Therefore, we have

$2x+1-(x+3)=x-7-(2x+1)$

Distributing the negative over the parenthesis, we get

$2x+1-x-3=x-7-2x-1$

Combine like terms on both sides

$x-2=-x-8$

Add x to both sides

$2x-2=-8$

Add 2 to both sides

$2x=-6$

Divide both sides by 2

$x=-3$

Thus, the value of x is -3.