Question

Q3-In an isosceles triangle,AB=AC and AD,BE,CF are perpendiculars on the sides BC,AC, and AB respectively. The triangle is symmetrical about
​

Answer 1

Answer:

Given, from the vertices B and C of triangle ABC, the perpendiculars BE and CF are drawn on the opposite sides AC and AB respectively.

Again BE = CF

Again from the figure,

In ∆ FBC and ∆ ECB,

BE = CF (Given and also Hypoteneus of the two triangles)

∠ BEC= ∠ CFB (Perpendicular angles)

BC = BC (common side of two triangles)

So, from RHS congruence,

∆ FBC ≅ ∆ ECB

By CPCT,

∠ FBC = ∠ ECB (CPCT)

Hence, ∆ ABC is an isosceles triangle.

Answer 2

Answer:

Hope these attachments helps you