Question

Q3 Motion of a truck moving on a straight road is indicated in the table given below:
Speed(m/s) 5 10 15 25 35 50
Time(s) 0 10 20 30 40 50
(a)Determine the acceleration of the car between the last 10 secs.
(b) What was the distance travelled at the end of 20 secs

Answer 1

Answer:

Step-by-step explanation:

BRAINLEST PLZ

Answer 2

Answer:

Step-by-step explanation:

Graph of the table : Draw X - axis and Y - axis on the  graph with appropriate scale.  

Let 1 cm = 10 s on X-axis.  

Let 1 cm = 5 m on Y-axis.

(i) Acceleration means slope of graph AB  

BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2

(ii) Distance travelled by truck = Area of trapezium OABD  

= 1 /2 (AO + BD) × OD

= 1 / 2 (5 + 30) × 50 = 875 m