Question

Q3. Teacher has given one expression 2x + 3 = 7 and guided the students to put various values of x (0,1,2,3) and check which value of x satisfies the given equation. Is there any possibility Where x can have two or more values for the given equation?​

Answer 1

Answer:

1) let us take the value for x = 0

2x+3=7

2×0+3=7

2+3 is not equal to 7

so it is not possible

2) let us take the value for x = 1

2x+3=7

2×1+3=7

2+3 is not equal to 7

so it is not possible

3) now let us take the valuy for x = 2

2x+3=7

2×2+3=7

4+3=7

so,

therefore x = 2

Answer 2

Given,

Teacher given one expression $2x+3=7$

Put various values of $x(0,1,2,3)$

Step1: put $x=0$

$2x+3=7$

$2\times0+3=7\\3\neq 7$

Step 2: put $x=1$

$2\times1+3=7\\5\neq 7$

Step3: put $x=2$

$2\times2+3=7\\7=7$

Step4: put $x=3$

$2\times3+3=7\\9\neq 7$

The power of $x$ in the given equation is $1$

Therefore, the possibility of $x$ value can not have two or more values.

The value of $x$ is $2$.