Question

Q3. The base and height of a right-
angled triangle is 4.6 cm and 2.2 cm.
Find its area.
​

Answer 1

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Given :-

❍ Base and height of right - angled ㅤㅤㅤtriangle is 4.6 cm and 2.2 cm.

To Find :-

❍ It's area!!

Diagram :-

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(-0.3,2.5){\large\bf 2.2cm}\put(2.8,.6){\large\bf 4.6cm}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\end{picture}$

Solution :-

Area of right angled triangle = ½ × base × height.

Putting all values :-

➱ $\dfrac{1}{2}$ × 4.6 × 2.2

➱ $\dfrac{10.12}{2}$

➱ $\cancel{\dfrac{10.12}{2}}$

➱ 5.06

•°• Area of triangle = 5.06 cm².

NOTE :-

◍ Dear user if u are not able to see the diagram correctly in app. Pls see the diagram from the site (brainly.in) . It will be correctly displayed there.

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Answer 2

• Area of triangle is 5.06 cm².

Step-by-step explanation :

Given :-

• The base of right angle triangle is 4.6 cm.
• The height of right angle triangle is 2.2 cm.

To find :-

• Area of triangle.

Solution :-

Diagram of triangle :-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(-1,2.5){\large\bf 2.2\ cm}\put(2.4,.3){\large\bf 4.6\ cm}\put(1.02,1.02){\framebox(0.3,0.3)}\end{picture}$

Now,

According to question :-

$\boxed{\sf \bold{Area\: of \: triangle = \dfrac{1}{2} \times base \times height}}$

Here, Perpendicular is our height.

So, Put height and base in formula :

$\sf \longrightarrow Area_{(Triangle)} = \dfrac{1}{2} \times 4.6 \times 2.2$

$\sf \longrightarrow Area_{(Triangle)} = \dfrac{10.12}{2}$

$\sf \longrightarrow \purple{ \boxed{ \sf \bold{Area_{(Triangle)} = 5.06}}\bigstar}$

Therefore,

Area of triangle is 5.06 cm².