Q3. The Diagonals of a
rhombus measure 24cm and
10 cm. Find its perimeter.
Answers
Answer:
52 cm
Step-by-step explanation:
Given : Diagonals of the rhombus
Let d1 =10cm and d2= 24cm
To Find : The perimeter of the given rhombus
Solution : Diagonals meet at the centre and forms right-angled triangles.
So by using pythagoras theorem
Length of the base = 10/2 = 5cm
Length of the height = 24/2 = 12cm
Hypotenuse2 = side 2+ side2
Hypotenuse2= 52+ 122
.
Hypotenuse2 = 25 + 144
Hypotenuse2 = 169
On taking square root we get,
Hypotenuse = 13 { 13 X 13=169 => √169=13}
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.
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Answer:
So the answer is 52cm.....
Hope it works......
Step-by-step explanation:
Diagonals of the rhombus
Let d1 =10cm and d2= 24cm
Find out
We need to find the perimeter of the given rhombus
Solution
Diagonals meet at the centre and forms right-angled triangles.
So by using pythagoras theorem
Length of the base = 10/2 = 5cm
Length of the height = 24/2 = 12cm
Hypotenuse2 = side 2+ side2
Hypotenuse2= 52+ 122
Hypotenuse2 = 25 + 144
Hypotenuse2 = 169
On taking square root we get,
Hypotenuse = 13 { 13 X 13=169 => √169=13}
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.