Question

Q3) The factors of x3 - 361x are:​

Answer 1

Answer:

$x( {x} + 19)( {x} - 19)$

Step-by-step explanation:

Let

${x}^{3} - 361x = 0$

x is common in both the terms

$x( {x}^{2} - 361) = 0$

$x( {x}^{2} - {19}^{2} ) = 0$

Since this is in

$( {a}^{2} - {b}^{2} ) = (a + b)(a - b)$

Here a = x, b = 19

$x( {x} - 19)(x + 19) = 0$

$x(x + 19)(x - 19) \: are \: the \: factors .$