Math, asked by tina00, 1 month ago

Q3) The total number of tickets distributed for 3 shows in a cinema hall were 56, 28 and
70respectively. They were equally distributed among vvarious persons.
a) What is the maximum number of persons that get these tickets?

Answers

Answered by sonigaur2002

1

Answer:

14

Step-by-step explanation:

H.C.F of 56, 28, 70

56= 2×2×2×7

28= 2×2×7

70= 2×5×7

HCF= 2×7= 14

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