Q3. Using the digits 1 to 9 (each exactly once), form three 3- digit numbers so that the second number is 2 times the first and the third number is 3 times the first.?
Answers
Answer:
Step-by-step explanation:
The question given has two conditions:
(1) Find three 3-digit numbers using digits 1 to 9.
(2) The second number should be twice the first and the third number should be three times the first.
Below, I give four solutions satisfying both the above conditions:
(1) First Number = 192, Second Number = 192*2 = 384 and Third Number = 192*3 = 576. Please note that 192, 384 and 576 has all the digits from 1 to 9.
(2) First Number = 219, Second Number = 219*2 = 438 and Third Number = 219*3 = 657.
(3) First Number = 273, Second Number = 273*2 = 546 and Third Number = 273*3 = 819.
(4) First Number = 327, Second Number = 327*2 = 654 and Third Number = 327*3 = 981.
All the above fours solutions satisfy both the given conditions.