Q3 What is the largest number that divídes 63. 35 and 77 leaving 7 as
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remainder in each case.
Answers
Answered by
8
63–7=56
35–7=28
77–7=70
We will find now HCF of 56, 28 ,70 :
56=2×2×2×7
28=2×2×7
70=2×5×7
HCF =2×7=14
So, the required highest number would be 14 Ans
hope it will helps you ☺️
Answered by
4
Answer:
28,14,35
Step-by-step explanation:
i) 63 - 7 = 56
the largest number that divides 56 is 28
Therefore the largest number that divides 63 leaving 7 as remainder is 28
ii) 35 - 7 = 28
the largest number that divides 28 is 14
Therefore the largest number that divides 35 leaving 7 as remainder is 14
iii) 77 - 7 = 70
the largest number that divides 70 is 35
Therefore the largest number that divides 77 leaving 7 as remainder is 25
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