Q33. An object of height 5 cm is held 30 cm away from a converging lens of focal length
10 cm. Find the position, size and nature of the image formed. 3
Answers
Given :
In convex lens,
Object height = 5cm.
Object distance = - 30cm
Focal length = 10cm.
To find :
The position, size and nature of the image formed.
Solution :
Using lens formula,
The formula which gives the relationship between image distance, object distance and focal length of a lens is known as the lens formula.
The lens formula can be written as :
where,
- v denotes image distance
- u denotes object distance
- f denotes focal length
by substituting all the given values in the formula,
thus, the position of image is 15cm.
Now, to find size of image we have to use magnification formula that is
where,
- m denotes magnification
- h' denotes image height
- h denotes object height
by substituting all the given values in the formula
thus, the size of image is 2.5cm
Nature of image
- The image is real and inverted.
- The image is diminished.
To find position and height of image .
1/f = 1/v - 1/u
1/10 = 1/v - 1/(-30)
1/10 = 1/v + 1/30
1/v = 1/10 - 1/30
1/v = 3-1/30
1/v = 2/30
1/v = 1/15 [ cross multiplication ]
v = 15
ho/hi = v/u
ho/5 = 15/-30
ho = 15×5/30
ho = 2.5cm
nature of image is = inverted ,large in size , real
I hope you will understand !!
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