Question

Q34- Find the smallest number by which 8788 must be duided so that
the questient is a berfect cube?​

Answer 1

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$8788$= $2×2×13×13×13$

Here,on grouping factors we found that $2$ does not appear in group of triplet.

So, $8788$ must be multiplied by 2 to make it a perfect cube.

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