Question

Q4:- find the product of the square of -2/3 and cube of -1/3​

Answer 1

Answer:

$\frac{-4}{243}$

Step-by-step explanation:

$=(\frac{-2}{3} )^{2} (\frac{-1}{3})^3\\ = (\frac{4}{9}) (\frac{-1}{27})\\= \frac{-4}{243}$

Answer 2

Answer:

$\frac{-4}{243}$

Step-by-step explanation:

First you need to find the square of $\frac{-2}{3}$ and the cube of $\frac{-1}{3}$

Like this: $-2^{2}$/$3^{2}$  and  $-1^{3}$/$3^{3}$,  you will get $\frac{4}{9}$ x $\frac{-1}{27}$

Take the LCM. You will get: $\frac{-4}{243}$!

You can further simplify it if you want.

Hope this helps my Friend!