q4 if a car physics ch motion
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yash003:
i need full answers
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You can use the eqautions of kinetics when solving questions that include uniform acceleration.
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Hello Friend,
Here,
Initially car was at rest. So,
• Initial velocity = u = 0 m/s
• Final velocity = v = 144 km/h = 40 m/s
[1 km/h = 1000m / 3600s = 5/18 m/s]
[So, v = 144 × 5/18 m/s = 40 m/s]
• Let acceleration = a m/s²
• Time elapsed = t = 20 sec
• Let distance travelled = s metres
→ Now, we will first find acceleration:
v = u + at
So, 40 = 0 + a(20)
So, a = 40/20
So, a = 2 m/s²
→ Now, we can find distance travelled:
s = ut + ½ at²
So, s = (0)(20) + ½ (2)(20)²
So, s = 0 + 400
So, s = 400 m
→ Thus, distance travelled in 20 seconds is 400 metres. [Option B]
Hope it helps.
Purva
@Purvaparmar1405
Brainly.in
Here,
Initially car was at rest. So,
• Initial velocity = u = 0 m/s
• Final velocity = v = 144 km/h = 40 m/s
[1 km/h = 1000m / 3600s = 5/18 m/s]
[So, v = 144 × 5/18 m/s = 40 m/s]
• Let acceleration = a m/s²
• Time elapsed = t = 20 sec
• Let distance travelled = s metres
→ Now, we will first find acceleration:
v = u + at
So, 40 = 0 + a(20)
So, a = 40/20
So, a = 2 m/s²
→ Now, we can find distance travelled:
s = ut + ½ at²
So, s = (0)(20) + ½ (2)(20)²
So, s = 0 + 400
So, s = 400 m
→ Thus, distance travelled in 20 seconds is 400 metres. [Option B]
Hope it helps.
Purva
@Purvaparmar1405
Brainly.in
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