Q4)In a parallelogram PQRS, if &P= (3x+10)°, and <Q = (2x-15) then find the angleQ
Answers
Answered by
1
Answer:
P + Q = 180o [Angles on the same side of a transversal are supplementary]
3x - 5 + 2x + 15 = 1800
5x = (180 - 10)0
5x = 170o
x = 34o
Answered by
1
Answer:
59 degrees
Step-by-step explanation:
3x+10+2x-15=180(Co-interior angles)
5x-5=180
5x=180+5
5x=185
x=185/5
x=37
Q=2x-15
Q=2×37-15
Q=74-15
Q=59 degrees
Similar questions