Q49. Some revolutionaries had thought that freedom can’t be attained with non-violence. Under this situation, HSRA was formed. What was its ideology and who were its leaders? What did they attempt?
Answers
Explanation:
Dimensions of a rectangular plot:
Let \: Length = l \: m \: and \: breadth = b \: mLetLength=lmandbreadth=bm
i) Perimeter \: of \: the \: plot = 36 \: mi)Perimeteroftheplot=36m
\implies 2( l + b ) = 36⟹2(l+b)=36
\implies l + b = \frac{36}{2}⟹l+b=
2
36
\implies b = 18 - l \: --(1)⟹b=18−l−−(1)
ii ) Area \: of\: the \: plot = l \times b \: --(2)ii)Areaoftheplot=l×b−−(2)
/* According to the problem given */
\begin{gathered} If \: the \: length \: is \: increased \: by \: 6\:m\\and \: the \: breadth \: is \: decreased \: by \\ 3\:m\: then \end{gathered}
Ifthelengthisincreasedby6m
andthebreadthisdecreasedby
3mthen
New Dimensions of the rectangular plot:
\begin{gathered} Length = ( l + 6 )\: m \: and \\breadth = ( b - 3 ) \: m \end{gathered}
Length=(l+6)mand
breadth=(b−3)m
Area \: of \: the \: new \: plot = ( l+6)(b-3) \:--(3)Areaofthenewplot=(l+6)(b−3)−−(3)
\pink{ (l+6)(b-3) = l \times b }(l+6)(b−3)=l×b
\implies l( b-3) + 6( b -3 ) = lb⟹l(b−3)+6(b−3)=lb
\implies \cancel {lb} - 3l + 6b - 18 =\cancel { lb}⟹
lb
−3l+6b−18=
lb
\implies -3l + 6b - 18 = 0⟹−3l+6b−18=0
/* Dividing each term by 3 , we get */
\implies - l + 2b - 6 = 0⟹−l+2b−6=0
\implies - l + 2( 18 - l ) = 6\: [ From \: ( 1 ) ]⟹−l+2(18−l)=6[From(1)]
\implies - l + 36 - 2l = 6⟹−l+36−2l=6
\implies - 3l = 6 - 36⟹−3l=6−36
\implies -3l = -30⟹−3l=−30
\implies l = \frac{ -30}{-3}⟹l=
−3
−30
\implies l = 10⟹l=10
Therefore.,
\red{ Length \: of \: the \: plot } \green { = 10\:m }Lengthoftheplot=10m
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