Q5.A brown coloured copper powder was placed in a china dish and was strongly heated in
air when a compound ‘X’ is formed. The compound ‘X’ was insoluble in water but dissolved
in dilute hydrochloric acid forming a greenish solution without evolution of any gas. Try to
answer the following questions based on the observations. (3)
(a) What is chemical formula and colour of compound X?
(b) Give chemical equation and category of the reaction involved.
(c) How X forms green coloured solution?
Answers
Answer:
(1) X is FeSO4 or Ferrous Sulphate. In the above experiment we have to consider FeSO4.7H2O. Blue Vitrol is the common name for copper sulphate or CuSO4. cliffffy4h and 3 more users found this answer helpful.
(2) These two solutions react to form a white insoluble precipitate.
BaCl
2
+Na
2
SO
4
→2NaCl+BaSO
4
↓
This is a double displacement reaction as the two compounds exchange their ions to form two different compounds.
(3) X is a copper. When the copper is exposed in air, a coating of green colour takes place on it. The process responsible for this is corrosion of copper. When a metal is attacked by substances around it such as moisture, acids, etc., it is said to corrode, and this process is called corrosion.
Explanation:
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