Question

Q5. Find the sum of all odd numbers between 100 and 200.
​

Answer 1

a=101

d=2

T=199

T=a+(n-1)d

199=101+(n-1)2

98=(n-1)2

46=n-1

n=47

sum=(n/2)(a+T)

sum=47/2 (101+199)

sum=47/2 (300)

sum=47×150

sum=7050

if it help

mark it as brainliest