Question

Q5. If -3 and 2 are roots of the quadratic equation x²-(p+2)x-q=0, then the values of p and q are: *

1 point

1) 3, -6

2) -3, 6

3) -3, -6

4) 3, 6

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Answer 1

Answer:

Step-by-step explanation:

p and q are the roots of the equation x2 + px + q = 0, then

p = 1 and q = -2

p = 0 and q = 1

p = -2 and q = 0

p = -2 and q = 1

Correct Option: A

Since, p and q are the roots of the equation x2 + px + q = 0

Then, p + q = - p

and pq = q

Now, pq = q

⇒ p = 1

Putting the value of p in p + q = - p, we get

1 + q = - 1

⇒ q = - 2

I HOPE IT HELPS YOU

Answer 2

Step-by-step explanation:

Given -

• -3 and 2 are roots of quadratic equation x² - (p + 2)x - q = 0

To Find -

• Value of p and q

Now,

p(x) = x² - (p + 2)x - q = 0

Then,

→ p(-3) = (-3)² - (p + 2)-3 - q = 0

→ 9 - (-3p - 6) - q = 0

→ 9 + 3p + 6 - q = 0

→ 3p - q = -15 .... (i)

And

p(2) = (2)² - (p + 2)2 - q = 0

→ 4 - (2p + 4) - q = 0

→ 4 - 2p - 4 - q = 0

→ -2p - q = 0 ..... (ii)

Now,

From (i) and (ii), we get :-

→ 3p - q = -15

-2p - q = 0

(+) (+)

____________

→ 5p = -15

→ p = -3

Now,

Substituting the value of p on -2p - q = 0, we get :-

→ -2(-3) - q = 0

→ 6 - q = 0

→ q = 6

Hence,

The value of p is -3 and q is 6

Therefore,

Option 2 is correct.