Question

Q5. The sides AB and DC of a cyclic quadrilateral
are produced to meet at P. The sides AD and BC
are produced to meet at Q
LADC= 85° and LBPC= 40° then
find LBAD
(ii) LCQD





Please helpp yaar !!​

Answer 1

ANSWER

∠ADC+∠ABC=180

→ supplementary due to being cyclically opposite angles

so ∠ABC=95

o

and ∠ABC+∠CBP=180

→ supplementary

∠CBP=85

o

then in triangle ΔBPC

∠B+∠P+∠C=180

o

∠C=55

o

∠ADC+∠QDC=180

→ supplementary

∠QDC=95

In triangle ΔDQC

⇒∠Q+∠D+∠C=180

o

so ∠Q=30

o

.

Answer 2

Answer:

∠ADC+∠ABC=180

→ supplementary due to being cyclically opposite angles

so ∠ABC=95  

o

 

and ∠ABC+∠CBP=180

→ supplementary

∠CBP=85  

o

 

then in triangle ΔBPC

∠B+∠P+∠C=180  

o

 

∠C=55  

o

 

∠ADC+∠QDC=180

→ supplementary

∠QDC=95

In triangle ΔDQC

⇒∠Q+∠D+∠C=180  

o

 

so ∠Q=30  

o

.

Step-by-step explanation: