Q5. What is the largest number
that divides 70 and 125, leaving
remainders 5 and 8
respectively?
Answers
Answer: 13
Step-by-step explanation:
Since, 5 and 8 are the remainders of 70 and 125, respectively.
Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70 – 5), 117 = (125−8), which is divisible by the required number.
Now, required number = HCF of 65, 117 [Since we need the largest number] For this, 117 = 65×1+52 [∵ dividend = divisor × quotient + remainder]
⟹ 65 = 52×1+13
⟹ 52 = 13×4+0
∴ HCF = 13
Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 and 8.
Answer:
To find the largest no. That devides 70 and 125, with leaving remaind 5 and 8 respectively.
First step:
We will have to substract 5 and 8 from the given no.s
70-5= 65
125-8= 117
Second step:
Now, we will compute H.C.F (Highest common factor) of 65 and 117.
65= 1×5×13
117=1×3×3×13
Common factor = 1×13
H.C.F = 13
The required answer is 13
Is the largest number which devides 70 and 125 with leaving remainder 5 and 8.