Question

Q52. The area of a rectangle is
30sq.cm. If its length is 6cm, what is
its breadth?
O
a. 4cm
O b. 35cm
O
c. 25cm
O d. 5cm​

Answer 1

Answer:

d.5cm is the correct answer

Answer 2

Answer:

Breadth (b) of the rectangle = 5cm.

  SOLUTION  

Area of the rectangle = 30cm².

Length of the  rectangle = 6cm.

Let us assume that the breadth of the rectangle is 'b' cm.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 6 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large b cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

Area of a rectangle =  l × b , Where l is the length and b is the breadth of the rectangle.

Here,

Area = 30cm².

l = 6cm .

b = b cm.

$\implies$ 30 = 6 × b

$\implies$ 30 = 6b

$\implies \sf b = \dfrac{30}{6}$

$\implies$ b = 5 cm.

Breadth of the rectangle = 5cm.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 6 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 5 cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

QUESTION FOR PRACTICE

The area of a rectangle is 50cm². If the breadth of the rectangle is 4cm, what is the length of the rectangle.

Answer (For Verification)

Length of the rectangle = 12.5 cm.