Physics, asked by vivankatyal2216, 6 months ago

Q6. (a) A car accelerates at a constant rate of 1.83 m/s2 along a fiat straight road. The car
accelerates from rest for 16 seconds. Calculate the speed of the car after 16 seconds​

Answers

Answered by Atαrαh
8

Question:

A car accelerates at a constant rate of 1.83 m/s2 along a fiat straight road. The car

accelerates from rest for 16 seconds. Calculate the speed of the car after 16 seconds

Given :

  • acceleration of the car = 1.83 m/s²
  • initial velocity of the car = 0 m/s²
  • time taken = 16 sec

To find :

  • final velocity of the car

Solution :

By using the first kinematic equation ,

 \bigstar \:  \large{ \boxed{ \green{v = u + at}}}

here ,

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time taken

Substituting the given values in the above equation we get ,

 \rightarrow  \large\mathtt{v = at}

\rightarrow  \large\mathtt{v = 1.83 \times 16}

\rightarrow  \large\mathtt{v = 29.28 \frac{m}{s} }

The speed of the car after 16 second is 29.28 m/s

Other formulas :

 \bigstar \:  \large{ \blue{s = ut +  \dfrac{1}{2}a {t}^{2}  }}

 \bigstar \:  \large{ \blue{ {v}^{2}  =  {u}^{2}  + 2as}}

 \bigstar \:  \large{ \blue{s = u +  \dfrac{a}{2} (2n - 1)}}

Answered by mayajakhar79
11

Question:

A car accelerates at a constant rate of 1.83 m/s2 along a fiat straight road. The car

accelerates from rest for 16 seconds. Calculate the speed of the car after 16 seconds

Given :

acceleration of the car = 1.83 m/s²

initial velocity of the car = 0 m/s²

time taken = 16 sec

To find :

final velocity of the car

Solution :

By using the first kinematic equation ,

\bigstar \: \large{ \boxed{ \green{v = u + at}}}

Here ,

v = final velocity

u = initial velocity

a = acceleration

t = time taken

Substituting the given values in the above equation we get ,

\rightarrow \large\mathtt{v = at}

\rightarrow \large\mathtt{v = 1.83 \times 16}

\rightarrow \large\mathtt{v = 29.28 \frac{m}{s} }

The speed of the car after 16 second is 29.28 m/s

Other formulas :

\bigstar \: \large{ \blue{s = ut + \dfrac{1}{2}a {t}^{2} }}

\bigstar \: \large{ \blue{ {v}^{2} = {u}^{2} + 2as}}

\bigstar \: \large{ \blue{s = u + \dfrac{a}{2} (2n - 1)}}

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