Question

Q6. An object is released from a height of 80m above the ground find the velocity when it reaches the ground. if time is not given​

Answer 1

Answer:

40 m/s

Explanation:

u=0 m/s

a=g=10 m/s^2

s=80m

using third equation of motion

v^2-u^2=2as

v^2-0=2x10x80

v^2=1600

v=√1600

v= 40 m/s

Answer 2

Answer:

Therefore velocity is 40 m/s

Explanation:

s = h =80 m

a = g = 110 m/s²   ( I chose 10m/s²  instead of 9.8 m/s² for easy calculation )

u  = 0 m/s ( It's starting from a stationary position )

v = ?

v²  - u²  = 2as

v² - 0²  = 2 * 10 * 80             ( a = g = 10 m/s², s = h = 80 m )

v²  = 1600

v = √1600 = 40

Therefore velocity is 40 m/s