Question

Q6. At residential area sector 22, if 500 crackers were burnt to produce 80 db of noise

pollution. How many crackers they should burst so that only 50 db of noise

pollution is created? ​

Answer 1

Answer:

312.5 crackers

Step-by-step explanation:

This problem is simply related to linear interpolations where one relation can be used to deduce another data based on the fact that the relationship is linear.

As per given data, we know that more the crackers more will be the noise of them, hence we can write the equation as

500 / C = 80 / 50

C = 500 x 50 / 80

C = 312.5

Answer 2

50 db of noise is produced by bursting 313 crackers.

Step-by-step explanation:

Let number of crackers required to produce 50 db be 'x'

The number of crackers required to produce 80 db is 500

Now, we need to apply cross multiplication method,

500       80db

        ×

x             50 db

Now,

500 × 50 = 80x

25000 = 80x

2500 = 8x

x = 2500/8

∴ x = 312.5 ≈ 313